In a Delta-Wye System, if the phase voltage of the Delta generator is 600V, what is the voltage of the load?

In a Delta-Wye (Δ-Y) transformation, the phase voltage in the Delta configuration is related to the line voltage in the Wye configuration. In a Delta system, the line voltage is equal to the phase voltage, but when shifting to a Wye system, the relationship between the line voltage and the phase voltage is different.

The formula to find the phase voltage in a Wye system from a Delta system is given by:

[ V_{phase} = \frac{V_{line}}{\sqrt{3}} ]

In this case, the line voltage (which is equal to the phase voltage in the Delta system) is 600V. Therefore, to find the phase voltage across the load in the Wye configuration, we can apply the formula:

[ V_{phase} = \frac{600V}{\sqrt{3}} ]

Calculating this gives:

[ V_{phase} \approx \frac{600}{1.732} \approx 346V ]

Thus, the voltage of the load in the Wye configuration is approximately 346V. This is why the correct answer is 346V, as it accurately reflects the transformation between the Delta and Wye configurations relative to the provided phase voltage.